$$ \scriptsize \text{Note: Figure not drawn to scale.} $$
Triangles \(ABC\) and \(DEF\) are similar. How much longer than segment \(BC\) is segment \(AB\)?
Approach
The corresponding parts of similar triangles must follow the same ratio. Since \(\dfrac{DF}{AC}=\dfrac{20}{4}\), the larger triangle is 5 times the size of the smaller triangle.
Therefore,
$$ BC = \frac{EF}{5} $$
$$ BC = \frac{21}{5} $$
$$ AB = \frac{DE}{5} $$
$$ AB= \frac{29}{5} $$
Triangles \(ABC\) and \(DEF\) are similar. How much longer than segment \(BC\) is segment \(AB\)?