Solve for \(k\).
$$6 \cdot 2k = 72 $$
$$ 2k=12 $$
$$ k=6 $$
Substitute our value of \(k\) into the expression \(2k-4\).
$$ 2k-4$$
$$2(6)-4$$
$$12-4$$
$$8$$
We can reduce the number of steps by recognizing that \(2k\) is present in the initial equation and final expression.
$$6 \cdot 2k = 72 $$
$$ 2k=12 $$
Subtract 4 from both sides.
$$2k-4=12-4$$
$$2k-4=8$$