What value of \(x\) satisfies the equation below?
$$ x+2x+3x+4x-1-2=3+5x+6x $$
\(\dfrac{6}{21}\)
\(-\dfrac{6}{21}\)
\(-6\)
\(6\)
Summary
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Approach
Combine like terms.
$$ x+2x+3x+4x-1-2=3+5x+6x $$ $$ \underbrace{x+2x+3x+4x}_{\text{linear terms}}\underbrace{-1-2}_{\text{constant terms}}=3+\underbrace{5x+6x}_{\text{linear terms}} $$ $$ 10x-3=3+11x $$ $$-6=x$$