What value of
x
x
x
satisfies the equation below?
x
+
2
x
+
3
x
+
4
x
−
1
−
2
=
3
+
5
x
+
6
x
x+2x+3x+4x-1-2=3+5x+6x
x
+
2
x
+
3
x
+
4
x
−
1
−
2
=
3
+
5
x
+
6
x
6
21
\dfrac{6}{21}
21
6
−
6
21
-\dfrac{6}{21}
−
21
6
−
6
-6
−
6
6
6
6
Summary
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Approach
Combine like terms.
x
+
2
x
+
3
x
+
4
x
−
1
−
2
=
3
+
5
x
+
6
x
x+2x+3x+4x-1-2=3+5x+6x
x
+
2
x
+
3
x
+
4
x
−
1
−
2
=
3
+
5
x
+
6
x
x
+
2
x
+
3
x
+
4
x
⏟
linear terms
−
1
−
2
⏟
constant terms
=
3
+
5
x
+
6
x
⏟
linear terms
\underbrace{x+2x+3x+4x}_{\text{linear terms}}\underbrace{-1-2}_{\text{constant terms}}=3+\underbrace{5x+6x}_{\text{linear terms}}
linear terms
x
+
2
x
+
3
x
+
4
x
constant terms
−
1
−
2
=
3
+
linear terms
5
x
+
6
x
10
x
−
3
=
3
+
11
x
10x-3=3+11x
10
x
−
3
=
3
+
11
x
−
6
=
x
-6=x
−
6
=
x