During a 8-second time interval, the average acceleration $a$, in meters per second squared, of an object with a initial velocity of 5 meters per second is defined by the equation $a=\dfrac{v_f-5}{8}$, where $v_f$ is the final velocity of the object in meters per second. If the equation is rewritten in the form $v_f=xa+y$, where $x$ and $y$ are constants, what is the value of $y$?

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$$a=\dfrac{v_f-5}{8}$$ $$8a=v_f-5$$ $$v_f=8a+\colorbox{aqua}{$5$}$$ $$v_f+xa+\colorbox{aqua}{$y$}$$