During a 8-second time interval, the average acceleration \(a\), in meters per second squared, of an object with a initial velocity of 5 meters per second is defined by the equation \(a=\dfrac{v_f-5}{8} \), where \(v_f\) is the final velocity of the object in meters per second. If the equation is rewritten in the form \(v_f=xa+y\), where \(x\) and \(y\) are constants, what is the value of \(y\)?

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$$a=\dfrac{v_f-5}{8} $$ $$ 8a=v_f-5 $$ $$ v_f=8a+\colorbox{aqua}{$5$} $$ $$ v_f+xa+\colorbox{aqua}{$y$} $$