$$ 2ax-3ay=1$$

In the equation above, \(a\) is a nonzero constant. The graph of the equation in the \(xy\)-plane is a line. What is the slope of the line?

Summary Submit

We want to rearrange the terms so we obtain the form \(y=mx+b\), where \(m\) is the slope.

$$ 2ax-3ay=1 $$ $$ 2ax=1+3ay $$ $$ 2ax-1=3ay$$ $$ y= \frac{2ax-1}{3a} $$ $$ y=\frac{2ax}{3a}-\frac{1}{3a} $$ $$ y=\boxed{\frac{2}{3}}x-\frac{1}{3a}$$