What is \(h(2)-h(4) \), given that \(h(x)=2^x\)?
\(-12\)
\(4\)
\(12\)
\(16\)
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Approach
Evluate \(h(2)\) and \(h(4)\).
$$ h(x)=2^x $$ $$ h(2)=2^2 = 4 $$ $$ h(4)=2^4 = 16 $$
Accordingly,
$$ h(2)-h(4) $$ $$ =4-16$$ $$ = \boxed{-12} $$