Exponential functions can be modeled using the equation,
$$y=a(b)^x $$
\(a= \) initial value, or \(y\)-intercept
\(b= \) multiplier or growth factor
From the graph we can estimate the \(y\)-intercept and multipier. From the answer choices, the most reasonable \(y\)-intercept would be \((0,10)\).
Every time the \(x\) value is increased by 1, the \(y\) value approximately doubles, giving us a multiplier of 2.
With initial value 10 and multiplier 2,
$$y=a(b)^x $$
$$\boxed{y=10(2)^x}$$
We can derive an approximate equation by choosing points from the scatterplot. Using an approximate \(y\)-intercept \((0,10)\) to find \(a\).
$$y=a(b)^x $$
$$ 10=a(b)^0$$
$$10=a(1)$$
$$10=a$$
Using another point \((3,80)\) to find \(b\),
$$y=a(b)^x $$
$$80=10(b)^3$$
$$8=b^3$$
$$\sqrt[3]{8}=b$$
$$2=b$$
Substituting back in,
$$y=a(b)^x $$
$$\boxed{y=10(2)^x}$$