$$3^{3/n}(\sqrt[n]{2})$$

If $n$ is a positive integer, which of the following is equivalent to the expression above?

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When the degree of the root is the same, we can combine the terms inside. For example, $\sqrt{2}\cdot\sqrt{3}=\sqrt{6}$ . In our expression, the degree of the root is $n$ for both bases.

We can confirm by rewriting as fractional exponents. The denominator of the exponent is equivalent to the degree of the root.

$$3^{3/n}(\sqrt[n]{2})$$ $$=3^{\frac{3}{n}}\cdot 2^{\frac{1}{n}}$$

This is the expression in radical form:

$$\sqrt[n]{3^3} \cdot \sqrt[n]{2}$$ $$= \sqrt[n]{3^3\cdot 2}$$ $$=\boxed{\sqrt[n]{54}}$$