If we seperate the items inside the parenthesis:
(−1⋅8⋅x⋅x)32
We can take care of the 2 exponent first by doubling the terms inside the parenthesis.
(−1⋅8⋅x⋅x)2⋅31
(−1⋅−1⋅8⋅8⋅x⋅x⋅x⋅x)31
The negative values cancel each other out. The current exponent is equivalent to a cube root.
38⋅8⋅x⋅x⋅x⋅x
We can take out a x since there are three of them, but we should obtain the prime factors of 8 to see if anything else can be simplified.
32⋅2⋅2⋅2⋅2⋅2⋅x⋅x⋅x⋅x
=2⋅2⋅x⋅3x
=4x3x