$$ \ce{MnO4- + 5Fe^{2+} + 8H+ -> Mn^{2+} + 5Fe^{3+} + 4H2O} $$

In the reaction represented above, the number of \(\ce{MnO4-}\) ions that react must be equal to which of the following?

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First, check that the reaction is balanced. There should be the same number of atoms for each element and the net charge of each side should be equal.

In this case, the reaction is balanced. Therefore, the ratio of \(\ce{MnO4-}\) to \(\ce{Fe^{2+}}\) is simply the ratio of the coefficients.