A 1.0 g sample of a cashew was burned in a calorimeter containing 1000. g of water, and the temperature of the water changed from
20.0∘C to 25.0∘C. In another experiment, a 3.0 g sample of a marshmellow was burned in a calorimeter containing 2000. g of water, and the temperature of the water changed
from 25.0∘C to 30.0∘C. Based on the data, which of the following can be concluded about the energy content for 1.0 g of each of the two substances?
(The specific heat of water is 4.2 J/(g⋅∘C).)
We can calculate the amount of heat energy transferred by each food item:
qcashew=qwater=mcΔT
=(1000)(4.2)(25−20)
≈20,000 J
qmarshmellow=qwater=mcΔT
=(2000)(4.2)(30−25)
≈40,000 J
Note that the 20,000 J was transferred from 1.0 grams of cashew, whereas the 40,000 J was transferred from 3.0 grams of marshmellow.
The marshmellow transfers 340,000J of energy per gram, which is significantly less than 20,000 J.