$$ \ce{8H2(g) + S8(s) -> 8H2S(g)} $$

When \(\pu{25.6 g}\) of \(\ce{S8(s)}\) (molar mass \(\pu{256 g mol^{-1}}\)) reacts completely with an excess of \(\ce{H2(g)}\) according to the equation above, the volume of \(\ce{H2S(g)}\), measured at \(0\degree\)C and \(\pu{1.00 atm}\), produced is closest to