How many protons, neutrons, and electrons are in an \(\ce{^{56}_{26}Fe}\) atom?
$$ \begin{array}{c c c c}
& \text{Protons} & \text{Neutrons} & \text{Electrons} \\
\text{(A)} & 26 & 30 & 26 \\
\text{(B)} & 26 & 56 & 26 \\
\text{(C)} & 30 & 26 & 30 \\
\text{(D)} & 56 & 26 & 26 \\
\end{array} $$
The number of protons for atoms are always determined by the type of element. Iron always has 26 protons.
Since the atom is neutral, there will need to be 26 electrons as well.
The number 56 refers to the mass number, which is the sum of the protons and neutrons. Since there are 26 protons, there will be 30 neutrons.