If \(\displaystyle F(x)=\int\limits_0^x \sqrt{x^3-2}   dt\), then \(F'(3) = \)

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$$ F(x)=\int\limits_0^x \sqrt{x^3-2}   dt $$ $$ F'(x)=\sqrt{x^3-2} $$ $$ F'(3)=\sqrt{3^3-2} $$ $$ F'(2)=\sqrt{25} $$ $$ F'(2)=\boxed{5} $$