The Taylor power-series for a function f about x=0 converges to f for −1≤x≤1. The nth-degree Taylor polynomial for f about
x=0 is given by Pn(x)=k=1∑n(−1)kk2+k+1xk. Of the following, which is the smallest number M for which
the alternating power-series error bound guarantees that ∣f(1)−P4(1)∣≤M ?
Approach
∣f(1)−P4(x)∣ describes the difference between the actual value versus the value approximated by the Taylor power-series. This error margin will always be less than then aN+1, where N is the number of terms used in the approximation. In the question, we are using P4(1), which is the first four terms of the power-series. Therefore, the absolute value of the remainder will be less than the value of the 5th term.