The functions f and g are differentiable. For all x, f(g(x))=x and g(f(x))=x.
If f(3)=8 and f′(3)=9, what are the values of g(8) and g′(8) ?
Since we are given f(g(x))=x and g(f(x))=x, f and g must be inverse functions.
Since f(3)=8, g(8)=3.
We can use the chain rule to obtain the formula for g′(x):
f(g(x))=x
f′(g(x))⋅g′(x)=1
g′(x)=f′(g(x))1
g′(8)=f′(g(8))1
g′(8)=f′(3)1
g′(8)=91