If \(\ln(2x+y)=x+1 \), then \(\dfrac{dy}{dx} =\)

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$$ \ln(2x+y)=x+1$$ $$ \frac{1}{2x+y} \left(2+\frac{dy}{dx}\right) = 1 $$ $$ 2+\frac{dy}{dx}=2x+y $$ $$ \frac{dy}{dx} = \boxed{2x+y-2} $$