You may be tempted to say that the graph of f is increasing and has no critical points, but reflect that it is possible that there are points not shown in the table that are negative.
The graph of f would be concave up if values in the table were strictly increasing, but the values decrease, increase, and decrease.
Since f′(x) changes from decreasing to increasing somewhere from −3<x<0 and changes from increasing to decreasing somewhere from −1<x<2, the graph of f must have two inflection points minimum.