Let \(f\) be the function given by \(f(x)=\dfrac{(x-3)^3(x+4)}{(x-3)(x+2)} \). For which of the following values of \(x\) is \(f\) not continuous?

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Rational functions are continous at all intervals except for \(x\) values which cause the denominator to equal \(0\).

$$ (x-3)(x+2) \neq 0 $$ $$ x\neq3, -2 $$

There is a point discontinuity at \(x=3\) and an infinite discontinuity at \(x=-2\).