For all $\theta$ such that $\cos{\theta}\neq 0$ and $\sin{\theta}\neq 0$, which of the following expressions is equal to $\dfrac{\tan{\theta}}{\sec{\theta}}$ ?

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$$\frac{\tan{\theta}}{\sec{\theta}} = \tan{\theta}\cdot \frac{1}{\sec{\theta}}$$ $$= \frac{\sin{\theta}}{\cos{\theta}}\cdot \cos{\theta}$$ $$= \boxed{\sin{\theta}}$$