In \(\triangle{ABC}\) shown below, the given side lengths are in meters. Which of the following expressions gives the area, in square meters, of \(\triangle{ABC}\).

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If you draw an altitude from the base \(\overline{AC}\) up to point \(B\), we can make a right triangle. This triangle has a hypotenuse of 11, so we can use trigonometry to get the height of the triangle:

$$ \sin{30^\circ} = \frac{\text{height}}{11} $$ $$ \text{height} = 11\sin{30^\circ} $$

Using the area formula for the original triangle

$$ A= \frac{1}{2}bh $$ $$ A = \frac{1}{2}(10)(11\sin{30^\circ}) $$ $$ A = \boxed{\frac{1}{2}(11)(10)(\sin{30^\circ})} $$