For what value of \(a\) would the following system of equations have an infinite number of solutions?

$$ 2x-3y=6 $$ $$ 4x-6y=3a $$

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If two lines have infinite solutions, they must be the same line. We can double the first equation to obtain:

$$ 2(2x-3y) = 2(6) $$ $$ 4x-6y=12 $$

For the two lines to be the same,

$$ 3a=12 $$ $$ a=\boxed{4} $$