If \(x+y=26\) and \(x-y=14\), then \(y=\) ?
\(6\)
\(7\)
\(12\)
\(20\)
\(40\)
Summary
Submit
Skip Question
Approach
Subtract the equations (elimination):
$$ (x+y)-(x-y)= 26-14 $$ $$ 2y = 12 $$ $$ y = \boxed{6} $$