The equation $24x^2+2x=15$ has two solutions. What is the greater of the 2 solutions?

$\dfrac{3}{4}$

$\dfrac{4}{3}$

$\dfrac{5}{6}$

$\dfrac{7}{6}$

$\dfrac{11}{15}$

Approach 1

There are numerous ways to do this problem algebraically, but probably the easiest method is to set the equation equation to 0 and graph it with your calculator. Then, find the greater $x$-intercept/zero.

Approach 2

$$24x^2+2x=15 $$ $$ 24x^2+2x-15=0 $$ $$ (4x-3)(6x+5)=0 $$ $$ x=\frac{3}{4} \text{ and } -\frac{5}{6} $$