Quadratics Question 1

The equation $24x^2+2x=15$ has two solutions. What is the greater of the 2 solutions?

\dfrac{3}{4}

\dfrac{4}{3}

\dfrac{5}{6}

\dfrac{7}{6}

\dfrac{11}{15}

Approach 1

There are numerous ways to do this problem algebraically, but probably the easiest method is to set the equation equation to 0 and graph it with your calculator. Then, find the greater $x$ -intercept/zero.

Approach 2

24x^2+2x=15

24x^2+2x-15=0

(4x-3)(6x+5)=0

x=\frac{3}{4} \text{ and } -\frac{5}{6}