A solution is 5% alcohol and 95% water. A second solution is 20% alcohol and 80% water. If 2 gallons of the first solution are mixed with 1 gallon of the second solution, the resulting solution is what percent alcohol?

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The alcohol content of 2 gallons of the first solution:

$$ 2(0.05) = 0.1 $$

The alcohol content of 1 gallon of the second solution:

$$ 1(0.2) = 0.2 $$

The combined alcohol volume will be \(0.1+0.2 = 0.3\). We can divide this by the total volume to get the resulting solution alcohol percentage:

$$ \frac{0.3}{2+1} = \frac{0.3}{3}$$ $$ = \boxed{10\%} $$