In the standard $(x,y)$ coordinate plane, what is the slope of the line that contains $(-2,-2)$ and has a $y$-intercept of $1$ ?

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Use the slope-intercept equation to find the slope:

$$y=mx+b$$ $$-2 = m(-2)+1$$ $$-2 = -2m+1$$ $$-3 = -2m$$ $$m=\boxed{\frac{3}{2}}$$

Use the formula for slope:

$$m = \frac{y_2-y_1}{x_2-x_1}$$

We are given a point $(-2,-2)$ and the $y$-intercept, $(0,1)$.

$$m = \frac{1-(-2)}{0-(-2)}$$ $$m=\boxed{\frac{3}{2}}$$