For all $m$ such that $0\lt m \lt 1$, the value of $m^{-1}$ must be:

greater that $m$.

equal to $m$.

less than $m$, but greater than $0$.

equal to $0$.

less than $0$.

Approach 1

We can choose a value for $m$, such as $\dfrac{1}{2}$.

$$ m^{-1} $$ $$ \left(\frac{1}{2}\right)^{-1} = 2 $$

This only fits the first choice.

Approach 2

Taking a number to the negative first power is the same as taking the reciprocal of a number.

The reciprocal of any positive fraction less than 1 will always be larger than 1, and therefore larger than the fraction itself.