For all $m$ such that $0\lt m \lt 1$, the value of $m^{-1}$ must be:

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We can choose a value for $m$, such as $\dfrac{1}{2}$.

$$m^{-1}$$ $$\left(\frac{1}{2}\right)^{-1} = 2$$

This only fits the first choice.

Taking a number to the negative first power is the same as taking the reciprocal of a number.

The reciprocal of any positive fraction less than 1 will always be larger than 1, and therefore larger than the fraction itself.