$\left(\dfrac{27}{64}\right)^{-\frac{2}{3}} $ = ?

$-\dfrac{9}{16} $

$-\dfrac{9}{32} $

$\dfrac{9}{32} $

$\dfrac{16}{9} $

$\dfrac{32}{9} $

Approach 1

We can use our calculator to find the answer.

Approach 2

$$ \left(\frac{27}{64}\right)^{-\frac{2}{3}} $$ $$ = \left(\frac{64}{27}\right)^{\frac{2}{3}} $$ $$ = \left(\sqrt[3]{\frac{64}{27}}\right)^2 $$ $$ = \left(\frac{4}{3}\right)^2 $$ $$ = \boxed{\frac{16}{9}} $$