For what real number value of
x
x
x
is the equation
6
4
1
3
=
2
x
64^{\frac{1}{3}}=2^x
6
4
3
1
=
2
x
true?
1
3
\dfrac{1}{3}
3
1
2
2
2
4
4
4
6
6
6
8
8
8
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6
4
1
3
=
2
x
64^{\frac{1}{3}}=2^x
6
4
3
1
=
2
x
(
2
6
)
1
3
=
2
x
(2^6)^{\frac{1}{3}}=2^x
(
2
6
)
3
1
=
2
x
2
6
⋅
1
3
=
2
x
2^{6\cdot\frac{1}{3}} = 2^x
2
6
⋅
3
1
=
2
x
2
2
=
2
x
2^2 = 2^x
2
2
=
2
x
x
=
2
x=\boxed{2}
x
=
2