For what real number value of \(x\) is the equation \(64^{\frac{1}{3}}=2^x\) true?
\(\dfrac{1}{3}\)
\(2\)
\(4\)
\(6\)
\(8\)
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$$ 64^{\frac{1}{3}}=2^x $$ $$ (2^6)^{\frac{1}{3}}=2^x $$ $$ 2^{6\cdot\frac{1}{3}} = 2^x $$ $$ 2^2 = 2^x $$ $$ x=\boxed{2} $$