Given \(x=5\), \(y=3\), and \(z=-6\), \((x+y-z)(y+z)\) = ?
\(-42\)
\(-6\)
\(6\)
\(11\)
\(18\)
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Approach
$$ (x+y-z)(y+z) $$ $$ =(5+3-(-6))(3+(-6)) $$ $$ =(5+3+6)(-3) $$ $$ = (14)(-3) = \boxed{-42} $$