Which of the following expressions is equivalent to $\dfrac{x^2+4x-12}{x^2-36}$ for $x^2-36\neq 0$ ?

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$$\frac{x^2+4x-12}{x^2-36}$$ $$=\frac{(x+6)(x-2)}{(x+6)(x-6)}$$ $$= \boxed{\frac{x-2}{x-6}}$$