Which of the following expressions is equivalent to \(\dfrac{x^2+4x-12}{x^2-36}\) for \(x^2-36\neq 0\) ?

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$$ \frac{x^2+4x-12}{x^2-36} $$ $$ =\frac{(x+6)(x-2)}{(x+6)(x-6)} $$ $$ = \boxed{\frac{x-2}{x-6}} $$