The expression \((4c-3d)(3c+d)\) is equivalent to:
\(12c^2-13cd-3d^2\)
\(12c^2-13cd+3d^2\)
\(12c^2-5cd-3d^2\)
\(12c^2-5cd+3d^2\)
\(12c^2-3d^2\)
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$$ (4c-3d)(3c+d) = (4c)(3c)+(4c)(d)+(-3d)(3c)+(-3d)(d) $$ $$ = 12c^2+4cd-9cd-3d^2 $$ $$ = \boxed{12c^2-5cd-3d^2} $$