For \(7y=2x-5\), which of the following expressions gives \(x\) in terms of \(y\) ?
\(\dfrac{7y-5}{2}\)
\(\dfrac{7y+5}{2}\)
\(\dfrac{7}{2}y-5\)
\(\dfrac{7}{2}y+5\)
\(5y+5\)
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$$ 7y=2x-5 $$ $$ 7y+5 = 2x $$ $$ x = \boxed{\frac{7y+5}{2}} $$