If \(i=\sqrt{-1}\), then \(\dfrac{i+i^2+i^3}{i^3+i^4+i^5}\) = ?

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$$ \frac{i+i^2+i^3}{i^3+i^4+i^5} $$ $$ = \frac{i-1-i}{-i+1+i} $$ $$ = \frac{-1}{1} $$ $$ = \boxed{-1} $$