For \(i=\sqrt{-1}\), \((2+2i)^2\) = ?
\(-16\)
\(0\)
\(8i\)
\(4+2i\)
\(4+4i\)
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Approach
$$ (2+2i)^2 = (2+2i)(2+2i) $$ $$ = 4+4i+4i+4i^2 $$ $$ = 4+8i-4 $$ $$ = \boxed{8i} $$