For \(i=\sqrt{-1}\), \((3+i)^2\) = ?
\(-9\)
\(8\)
\(8+6i\)
\(6+i\)
\(6+2i\)
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Approach
$$ (3+i)^2 = (3+i)(3+i) $$ $$ = 9 +3i+3i+i^2 $$ $$ = 9+6i-1 $$ $$ = \boxed{8+6i} $$