Quadrant I of the standard \((x,y)\) coordinate plane is shown on a large computer screen. A blinking dot is positioned at \((2,3)\). The dot makes exactly 2 moves: first, horizontally in the positive \(x\) direction for 4 seconds at a speed of 0.5 coordinate units per second; then, vertically in the positive \(y\) direction for 2 seconds at the same speed. At what point is the dot located after these 2 moves?

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The first move:

$$ \frac{0.5\text{ right}}{\text{second}} \cdot 4\text{ seconds} = 2\text{ right} $$

Second move:

$$ \frac{0.5\text{ up}}{\text{second}} \cdot 2\text{ seconds} = 1\text{ up} $$ $$ (2,3) \implies (2+2, 3+1) $$ $$ = \boxed{(4,4)} $$